How to calculate the pushing force

When an object is placed in a liquid, the liquid exerts pressure on all sides of the object . The pressure from below exerts a force on the object that pushes it up, so we can define the force of thrust as the force that occurs when an object is submerged in water.

If the object is less dense than the liquid, it will float. Even if the object is denser than water, the buoyancy pushes the object up and changes the perceived weight. Archimedes discovered that the force with which the fluid pushes a submerged object is equal to the weight of the water that displaces the object. If you want to know how to calculate the force of pushing on an object, do not stop reading this article from.

You will need to:
  • balance
  • Glass of water
Steps to follow:

one

In order to calculate the pushing force of a liquid, the first thing you have to do is measure the mass of the object in grams with the spring scale hanging. The weight of this object is the real mass and we will name it (m1).

Let's imagine that m1 = 300 gr

two

With the object still hanging from the spring balance, lower the object in the water until it floats or the object is completely submerged. Now you can measure the mass of the object in the liquid, we will call this mass (m2).

Let's imagine that m2 = 120 gr

3

Subtract the mass of the object in the water (m2) with the object's true mass (m1) out of the water. This is equivalent to the mass of water in grams displaced by the object (m3). For example, (m1) - (m2) = (m3).

m3 = 300 - 120 = 180 gr

4

Divide the result by 1000 to convert grams to kilograms. For example, (m3 in grams) x 1 kg / 1, 000 g = (m3 in kilograms).

m3 = 180 gr / 1000 g = 0.18 kg

5

Finally to determine the pushing force on an object, you will have to multiply the previous result of the m3 (remember that the result has to be in Kg) by the gravity of the earth that is equal to 9.81 meters / second.

N = 0.18 x 9.81 = 1.76 kg · m / s2